strncpy, strncpy_s
From cppreference.com
Defined in header
<string.h>
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||
(1) | ||
char *strncpy( char *dest, const char *src, size_t count );
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(until C99) | |
char *strncpy( char *restrict dest, const char *restrict src, size_t count );
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(since C99) | |
errno_t strncpy_s(char *restrict dest, rsize_t destsz,
const char *restrict src, rsize_t count); |
(2) | (since C11) |
1) Copies at most
count
characters of the character array pointed to by src
(including the terminating null character, but not any of the characters that follow the null character) to character array pointed to by dest
.
If
count
is reached before the entire array src
was copied, the resulting character array is not null-terminated.
If, after copying the terminating null character from
src
, count
is not reached, additional null characters are written to dest
until the total of count
characters have been written.
The behavior is undefined if the
dest
array is not large enough. The behavior is undefined if the character arrays overlap. The behavior is undefined if either dest
or src
is not a pointer to a character array.
2) Same as (1), except that the function does not continue writing zeroes into the destination array to pad up to
count
, it stops after writing the terminating null character (if there was no null in the source, it writes one at dest[count] and then stops). Also, the following errors are detected at runtime and call the currently installed constraint handler function:
-
src
ordest
is a null pointer -
destsz
orcount
is zero or greater than RSIZE_MAX -
count
is greater or equaldestsz
, butdestsz
is less or equal strnlen_s(src, count), in other words, truncation would occur - overlap would occur between the source and the destination strings
-
The behavior is undefined if the size of the character array pointed to by
dest
< strnlen_s(src, destsz) <= destsz
; in other words, an erroneous value of destsz
does not expose the impending buffer overflow. The behavior is undefined if the size of the character array pointed to by src
< strnlen_s(src, count) < destsz
; in other words, an erroneous value of count
does not expose the impending buffer overflow.- As all bounds-checked functions,
strncpy_s
is only guaranteed to be available if __STDC_LIB_EXT1__ is defined by the implementation and if the user defines __STDC_WANT_LIB_EXT1__ to the integer constant 1 before includingstring.h
.
Contents |
[edit] Parameters
dest | - | pointer to the character array to copy to |
src | - | pointer to the character array to copy from |
count | - | maximum number of characters to copy |
destsz | - | the size of the destination buffer |
[edit] Return value
1) returns a copy of
dest
2) returns zero on success, returns non-zero on error. Also, on error, writes zero to dest[0] (unless
dest
is a null pointer or destsz
is zero or greater than RSIZE_MAX) and may clobber the rest of the destination array with unspecified values.[edit] Notes
As corrected by the post-C11 DR 468, strncpy_s
, unlike strcpy_s, is only allowed to clobber the remainder of the destination array if an error occurs.
Unlike strncpy
, strncpy_s
does not pad the destination array with zeroes, This is a common source of errors when converting existing code to the bounds-checked version.
Although truncation to fit the destination buffer is a security risk and therefore a runtime constraints violation for strncpy_s
, it is possible to get the truncating behavior by specifying count
equal to the size of the destination array minus one: it will copy the first count
bytes and append the null terminator as always: strncpy_s(dst, sizeof dst, src, (sizeof dst)-1);
[edit] Example
Run this code
#define __STDC_WANT_LIB_EXT1__ 1 #include <string.h> #include <stdio.h> #include <stdlib.h> int main(void) { char src[] = "hi"; char dest[6] = "abcdef"; // no null terminator strncpy(dest, src, 5); // writes five characters 'h', 'i', '\0', '\0', '\0' to dest printf("strncpy(dest, src, 5) to a 6-byte dest gives : "); for(size_t n = 0; n < sizeof dest; ++n) { char c = dest[n]; c ? printf("'%c' ", c) : printf("'\\0' "); } printf("\nstrncpy(dest2, src, 2) to a 2-byte dst gives : "); char dest2[2]; strncpy(dest2, src, 2); // truncation: writes two characters 'h', 'i', to dest2 for(size_t n = 0; n < sizeof dest2; ++n) { char c = dest2[n]; c ? printf("'%c' ", c) : printf("'\\0' "); } printf("\n"); #ifdef __STDC_LIB_EXT1__ set_constraint_handler_s(ignore_handler_s); char dst1[6], src1[100] = "hello"; int r1 = strncpy_s(dst1, 6, src1, 100); // writes 0 to r1, 6 characters to dst1 printf("dst1 = \"%s\", r1 = %d\n", dst1,r1); // 'h','e','l','l','o','\0' to dst1 char dst2[5], src2[7] = {'g','o','o','d','b','y','e'}; int r2 = strncpy_s(dst2, 5, src2, 7); // copy overflows the destination array printf("dst2 = \"%s\", r2 = %d\n", dst2,r2); // writes nonzero to r2,'\0' to dst2[0] char dst3[5]; int r3 = strncpy_s(dst3, 5, src2, 4); // writes 0 to r3, 5 characters to dst3 printf("dst3 = \"%s\", r3 = %d\n", dst3,r3); // 'g', 'o', 'o', 'd', '\0' to dst3 #endif }
Possible output:
strncpy(dest, src, 5) to a 6-byte dst gives : 'h' 'i' '\0' '\0' '\0' 'f' strncpy(dest2, src, 2) to a 2-byte dst gives : 'h' 'i' dst1 = "hello", r1 = 0 dst2 = "", r2 = 22 dst3 = "good", r3 = 0
[edit] References
- C11 standard (ISO/IEC 9899:2011):
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- 7.24.2.4 The strncpy function (p: 363-364)
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- K.3.7.1.4 The strncpy_s function (p: 616-617)
- C99 standard (ISO/IEC 9899:1999):
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- 7.21.2.4 The strncpy function (p: 326-327)
- C89/C90 standard (ISO/IEC 9899:1990):
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- 4.11.2.4 The strncpy function
[edit] See also
(C11)
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copies one string to another (function) |
(C11)
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copies one buffer to another (function) |
C++ documentation for strncpy
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