std::allocator::allocate
From cppreference.com
| pointer allocate( size_type n, std::allocator<void>::const_pointer hint = 0 );
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Allocates n * sizeof(T) bytes of uninitialized storage by calling ::operator new(std::size_t), but it is unspecified when and how this function is called. The pointer hint may be used to provide locality of reference: the allocator, if supported by the implementation, will attempt to allocate the new memory block as close as possible to hint.
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[edit] Parameters
| n | - | the number of objects to allocate storage for |
| hint | - | pointer to a nearby memory location |
[edit] Return value
Pointer to the first byte of a memory block suitably aligned and sufficient to hold an array of n objects of type T.
[edit] Exceptions
Throws std::bad_alloc if allocation fails.
[edit] See also
| [static]
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allocates uninitialized storage using the allocator (public static member function of std::allocator_traits)
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