std::make_signed
From cppreference.com
Defined in header
<type_traits>
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template< class T >
struct make_signed; |
(since C++11) | |
If T
is an integral (except bool) or enumeration type, provides the member typedef type
which is the signed integer type corresponding to T
, with the same cv-qualifiers.
Otherwise, the behavior is undefined.
Contents |
[edit] Member types
Name | Definition |
type
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the signed integer type corresponding to T
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[edit] Helper types
template< class T >
using make_signed_t = typename make_signed<T>::type; |
(since C++14) | |
[edit] Example
Run this code
#include <iostream> #include <type_traits> int main() { typedef std::make_signed<char>::type char_type; typedef std::make_signed<int>::type int_type; typedef std::make_signed<volatile long>::type long_type; bool ok1 = std::is_same<char_type, signed char>::value; bool ok2 = std::is_same<int_type, signed int>::value; bool ok3 = std::is_same<long_type, volatile signed long>::value; std::cout << std::boolalpha << "char_type is 'signed char'? : " << ok1 << '\n' << "int_type is 'signed int'? : " << ok2 << '\n' << "long_type is 'volatile signed long'? : " << ok3 << '\n'; }
Output:
char_type is 'signed char'? : true int_type is 'signed int'? : true long_type is 'volatile signed long'? : true
[edit] See also
(C++11)
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checks if a type is signed arithmetic type (class template) |
(C++11)
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checks if a type is unsigned arithmetic type (class template) |
(C++11)
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makes the given integral type unsigned (class template) |